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Author Topic: Gradient for trigonometric functions  (Read 937 times)
Eklav Rai
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« on: July 15, 2009, 06:52:28 AM »

A curve has the equation Y=2 tan2x - 7 tanx
Find:
(a) an expression for the gradient of the curve
(b) the X-coordinates of each of the stationary points of the curve.
« Last Edit: July 16, 2009, 11:19:39 AM by Tutor » Logged
Open Intelligence
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« Reply #1 on: July 16, 2009, 11:04:17 AM »

If this is an O-Level question, then the question should be y = 2tan 2x - 7tanx

(i) dy/dx (tan2x) = 2 tanx sec2x

dy/dx = 4 tanx sec2x - 7sec2x

(ii) at stationary points, dy/dx = 0

therefore, sec2x(4tanx - 7) = 0

sec 2 x = 0 (reject)

tanx = 7/4

x = tan -1 (7/4)
key angle = 1.05

x = 1.05, 4.19
« Last Edit: July 16, 2009, 11:19:17 AM by Tutor » Logged
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