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Additional Mathematics
Gradient for trigonometric functions
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Topic: Gradient for trigonometric functions (Read 937 times)
Eklav Rai
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Posts: 19
Gradient for trigonometric functions
«
on:
July 15, 2009, 06:52:28 AM »
A curve has the equation Y=2 tan2x - 7 tanx
Find:
(a) an expression for the gradient of the curve
(b) the X-coordinates of each of the stationary points of the curve.
«
Last Edit: July 16, 2009, 11:19:39 AM by Tutor
»
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Open Intelligence
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Re: Gradient for trigonometric functions
«
Reply #1 on:
July 16, 2009, 11:04:17 AM »
If this is an O-Level question, then the question should be y = 2tan
2
x - 7tanx
(i) dy/dx (tan
2
x) = 2 tanx sec
2
x
dy/dx = 4 tanx sec
2
x - 7sec
2
x
(ii) at stationary points, dy/dx = 0
therefore, sec
2
x(4tanx - 7) = 0
sec
2
x = 0 (reject)
tanx = 7/4
x = tan
-1
(7/4)
key angle = 1.05
x = 1.05, 4.19
«
Last Edit: July 16, 2009, 11:19:17 AM by Tutor
»
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